Pls help me with this question

Answer:
option C, x=1
Step-by-step explanation:
[tex]2^{9x-3} = 8^{3-x}[/tex]
[tex]2^{9x-3} = (2^3)^{3-x}[/tex]
[tex]2^{9x-3} = 2^{9-3x}[/tex]
cut 2 from LHS and RHS you will get,
9x-3 = 9-3x
9x + 3x = 9 + 3
12x = 12
x = 12/12
x = 1
therefore, option C is the correct option
hope it helps you!
Answer:
[tex] \huge{ \boxed{ \bold{ \tt{x = 1}}}}[/tex]
Option C is correct.
Step-by-step explanation:
[tex] \text{First ,\: let's \: know \: about \: exponential \: equation} : [/tex]
An equation in which variables appears as an exponent of a base is known as exponential equation. The following axioms are useful while solving the exponential equations :
Thus , while solving an exponential equation, we should simplify the equation till the equation is obtained in the form [tex] \sf{ {a}^{x} = {a}^{b}} [/tex] or aˣ = 1 .
Now, let's start to solve :
[tex] \sf{ {2}^{(9x - 3)} = {8}^{( 3 - x)}} [/tex]
➸ [tex] \sf{ {2}^{9x - 3} = {2}^{3(3 - x)} }[/tex]
➸ [tex] \sf{ {2}^{9x - 3} = {2}^{9 - 3x}} [/tex]
➸ [tex] \sf{ \cancel{2} ^{ \: 9x - 3} = \cancel{2} ^{ \: 9 - 3x} }[/tex]
➸ [tex] \sf{9x - 3 = 9 - 3x}[/tex]
➸ [tex] \sf{9x + 3x = 9 + 3}[/tex]
➸ [tex] \sf{12x = 12}[/tex]
➸ [tex] \sf{ \frac{12x}{12} = \frac{12}{12}} [/tex]
➸ [tex] \boxed{ \sf{x = 1}}[/tex]
The value of x is 1 .
Hope I helped!
Best regards! :D
~[tex] \text{TheAnimeGirl}[/tex]