Question

in the trapezoid below x = ?

Answer 1

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$\frac{(2x + 6) + (4x + 2)}{2} = 5x - 20$

$\frac{6x + 8}{2} = 5x - 20$

$\frac{2(3x + 4)}{2} = 5x - 20$

$3x + 4 = 5x - 20$

Subtract sides 4

$3x + 4 - 4 = 5x - 20 - 4$

$3x = 5x - 24$

Subtract sides 5x

$- 5x + 3x = - 5x + 5x - 24$

$- 2x = - 24$

Negatives simplifies

$2x = 24$

Divided sides by 2

$\frac{2}{2} x = \frac{24}{2}$

$x = 12$

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Answer 2

Answer:

x = 12

Step-by-step explanation:

The mid segment is half the sum of the 2 parallel bases, that is

5x - 20 = $\frac{2x+6+4x+2}{2}$

5x - 20 = $\frac{6x+8}{2}$ ( multiply both sides by 2 to clear the fraction )

10x - 40 = 6x + 8 ( subtract 6x from both sides )

4x - 40 = 8 ( add 40 to both sides )

4x = 48 ( divide both sides by 4 )

x = 12