Question

In a hydraulic press, a force of 20N is applied to a piston of area 2 meters square. If the area of the other piston is 4 meters square, calculate the force exerted on it

Answer 1

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$Pressure \: of \: piston(1) = Pressure \: of \: piston(2)$

$\frac{f(1)}{a(1)} = \frac{f(2)}{a(2)}$

$\frac{20}{2} = \frac{f(2)}{4}$

$10 = \frac{f(2)}{4}$

Multiply sides by 4

$4 \times 10 = 4 \times \frac{f(2)}{4}$

$40 = f(2)$

$f(2) = 40 \: \: N$

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