Question

Combined Variation:

The safe load for a horizontal beam supported at both ends varies
jointly as the width and the square of its depth and inversely as
the distance between the supports. If a 4 cm by 6 cm beam,
10 m long supports 5 kg when standing on the edge, what is the
safe load if the beam is turned on its side?

Answer 1

Answer:

The formula would be

wd^2c/l = p

(2*1^2c)/4 = 10

(2*1c)/4 = 10

2c/4 = 10

c = 20

3*2^2*20/6 = p

3*4*20/6 = p

240 pounds

hope it help :)

Step-by-step explanation: