Question

2(4z-1)=3(z+2)
Help?

Answer 1

This algebra question can only be solved by first distributing the numbers through their respective parentheses.
so 8z-2=3z+6
then, add 2 to both sides: 8z = 3z+8
then, subtract 3z from both sides: 5z = 8
Then, divide by 5: z = 8/5

Answer 2

2(4z-1)=3(z+2)
8z-2=3z+6             expand
8z-3z-2=3z-3z+6   subtract 3z from both sides
5z-2+2=6+2           add 2 on both sides
5z/5=8/5                divide 5 on both sides
z=8/5=1.6             solution