Answer:
The equation of the line that passes through the point (-7, -8) and parallel to the given line is y = 5/7·x - 3
Step-by-step explanation:
The coordinates of the point the line passes = (-7, -8)
The equation of the line the required line is parallel to is y = 5/7·x - 5
The slope of of the given line is therefore in slope and intercept form with the slope = 5/7 and the y-intercept = -5
The slope of a line parallel to another line are equal, therefore the slope of the required line = The slope of the given line = 5/7
The equation of the required line in point slope form is therefore;
y - (-8) = 5/7 × (x - (-7))
y + 8 = 5/7 × x + 5/7 × 7
y + 8 = 5/7 × x + 5
∴ y = 5/7 × x + 5 - 8 = 5/7 × x - 3
y = 5/7 × x - 3
The equation of the line that passes through the point (-7, -8) and parallel to y = 5/7x - 5 is y = 5/7·x - 3.
