Answer:
This function is defined! Look at 1st and 2nd portions. It is clearly defined at both f(0) and f(2)!
Check the correct answer by putting:
[tex]f(0)=(x+2)^2 -1=(0+2)^2-1=4-1=3[/tex]
and:
[tex]f(2)=-2+1=-1[/tex]
Therefore: [tex]f(0)>f(2)[/tex]. (Option 2)
