Question

Find the equation of a line that passes through the points (1, 2) and (5,8).

1: y= 3/2 + 1/2
2: y= 3/2 + 1
3: y= 3/2 + 2

Answer 1

Answer:

1: y = 3/2 + 1/2

Step-by-step explanation:

y1 -y2/x1 - x2

8-2 / 5-1

6/4 = 3/2

y-2=3/2(x-1)

y-2=3/2x - 3/2

y-2 +2= 3/2x - 3/2 +2

y=3/2x + 1/2