Question

A crane is lifting a 500-kg object at a constant speed of 0.5 m/s. What is the power output of the crane

Answer 1

Answer:

The power output is 2450 W

Explanation:

Give;

mass of the object, m = 500 kg

velocity of the object, v = 0.5 m/s

The power output is given  by the following equation;

P = F x V

Where;

P is the output power

F is the applied force

P = (mg) x v

P = ( 500 x 9.8) x 0.5

P = 2450 W

Therefore, the  power output is 2450 W

Answer 2

The power output of the crane is 2450 W.

What is power?

Power can be defined as the rate at which work is done.

To calculate the power output of the crane, we use the formula below.

Formula:

• P = mgv................ Equation 1

Where:

• P = Power output of the crane
• m = mass of the object
• v = speed
• g = acceleration due to gravity.

From the question,

Given:

• m = 500 kg
• g = 9.8 m/s²
• v = 0.5 m/s.

Substitute these values into equation 1

• P = 500(9.8)(0.5)
• P = 2450 W.

Hence, the power output of the crane is 2450 W.

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