Answer:
The volumetric flow through the pipe is 1.21 ft³/s
Explanation:
Given;
fluid mean velocity, v = 10 ft/s
outer diameter of the pipe, d₀ = 4.95 inches = 0.4125 ft
thickness of the pipe, x = 0.25 inches = 0.0208 ft
the inner diameter of the pipe, d₁ = d₀ - x = 0.4125 ft - 0.0208 ft = 0.3917 ft
the area of the pipe = [tex]A = \frac{\pi d_i^2}{4} = \frac{\pi * 0.3917^2}{4} = 0.121 \ ft^2[/tex]
The volumetric flow rate of the pipe is given by;
Q = Av
Q = (0.121 ft²) (10 ft/s)
Q = 1.21 ft³/s
Therefore, the volumetric flow through the pipe is 1.21 ft³/s
