Answer:
[tex]-949.97\ \text{J}[/tex]
Explanation:
[tex]P[/tex] = Pressure = [tex]1.02\ \text{atm}[/tex]
[tex]dv[/tex] = Change in volume = [tex](1.28-0.245)\ \text{L}[/tex]
[tex]q[/tex] = Emission of heat = [tex]843\ \text{J}[/tex]
Work done is given by
[tex]W=-Pdv\\\Rightarrow W=-1.02(1.28-0.245)\times 10^{-3}\times 101325\\\Rightarrow W=-106.97\ \text{J}[/tex]
Total energy of the system
[tex]E=W+q\\\Rightarrow E=-106.97-843\\\Rightarrow E=-949.97\ \text{J}[/tex]
The [tex]\Delta E[/tex] for the burning of the fuel is [tex]-949.97\ \text{J}[/tex].