Question

If the dresser is sliding with a constant velocity, find FFF, the magnitude of the force that the person applies.

Answer 1

Complete Question

The complete question is shown on the first uploaded image

Answer:

The force is  $F = mg \mu_k$

Explanation:

Generally the magnitude of the force the person applied is equivalent to the kinetic frictional force acting on the dresser

   So  

          $F = \mu_k * N$

Here N is the normal force acting on the dresser at point  P and  Q  that is  

     $N_p \ and \ N_Q$

So

      $F = \mu_k [N_p + N_Q]$

Generally this normal force is equal to  the mass of the dresser multiplied by the acceleration due to gravity so

     $N_P + N_Q = mg$

Hence  

        $F = mg \mu_k$