Question

A very long straight wire carries a 13.8-A current eastward, and a second very long straight wire carries a 12.7-A current westward. The wires are parallel to each other and are 20.5 cm apart. Calculate the resulting magnetic force on a 5.68-m length of one of the wires

Answer 1

Answer:

The resulting magnetic force is 9.712 x 10⁻⁴ N

Explanation:

Given;

current in the first wire, I₁ = 13.8 A

current in the second wire, I₂ = 12.7 A

distance between the wires, d = 20.5 cm = 0.205 m

length of the wire, L = 5.68 m

The resulting magnetic force is given  by;

$F = \frac{\mu_o I_1I_2L}{2\pi d} \\\\F = \frac{4\pi *10^{-7}(13.8*12.7) (5.68)}{2\pi (0.205)} \\\\F = 9.712 *10^{-4} \ N$

Therefore, the resulting magnetic force is 9.712 x 10⁻⁴ N.