Answer: 3.125
Step-by-step explanation:
Given: Proportion of defective widgets = [tex]p=\dfrac{1}{48}[/tex]
sample size : n= 150
Widgets either defective or not so it will follow binomial distribution.
Since . Mean = np
The mean (average) number of defective widgets in a batch of 150 widgets
[tex]=150\times\dfrac{1}{48}\\\\=3.125[/tex]
Hence, the mean (average) number of defective widgets in a batch of 150 widgets =3.125