Question

The steel and concrete in the left column are bonded so that there is no slip. What is the deformation in this column due to the applied load

Answer 1

Answer:

hello your question is incomplete attached below is the missing part of the question

Answer : ≈ 0.0284 mm

Explanation:

The deformation in the left column can  be calculated using this relationship

Deformation ( δ ) = $\frac{F_{1} * h}{A_{c}E_{c} + A_{s}E_{s} }$  --------- ( 1 )

Given :

Es = 200 GPa

Ec = 30 GPa

F1 = 41.9 KN ( as calculated )

$A_{c} = \frac{\pi }{4} * ( d_{c} ^2 - d_{s} ^2 )$ = 298.45$cm^2$

also

$A_{s} = \frac{\pi }{4} * d_{s} ^2$  = 153.94 $cm^2$

insert the given values into equation 1 above

Deformation ( δ ) = 2.84 * 10^-5 m ≈ 0.0284 mm