Answer:
9.7 seconds
Step-by-step explanation:
From the question, we know that the the skydiver falls under the force of gravity which means His initial velocity (U)= 0
We can calculate His displacement when he's under the influence of gravity by substracting the altitude when he opens his parachute from the altitude he jump with as
S= (2500 ft - 1000 ft)
= 1500 ft
The time taken can be gotten from the 2nd equation of motion which can be expressed mathematically as
Using second equation of motion:
S = u t + 0.5 a t²
Where a= 32ft/s^2 which is the acceleration due to gravity in feet.
S= displacement= 1500 ft
U= initial velocity when under gravity= 0
If all these values is substituted into the Newton equation, we have,
S = u t + 0.5 at²
S= (0×t) + at²
S= 0+at²
t²= S/a
t²= 1500/32
t²= 46.875
t= √46.875
t= 9.67 seconds
Therefore, it will take the the jumper approximately 9.7 seconds to fall before he opens his chute.
