Answer:
Step-by-step explanation:
in this problem we are expected to find the length/height of the photo
given
perimeter= 234in
let the height be x
width = 2x+6----------"The width is 6 in. more than twice the height."
we know that the perimeter is expressed as
P=2H+2W
P=2(x)+2(2x+6)
234=2(x)+2(2x+6)
solving for x we have
234=2x+4x+12
234-12=6x
222=6x
x=222/6
x=37in
the height is 37in
put x=37 in width = 2x+6
width = 2(37)+6
width = 74+6
width = 80in