Answer:
The length of the string changing when it is stretched out to 200 ft at rate 16.535 ft/min
Step-by-step explanation:
Refer the attached figure
Height of kite = y = 150 feet
We are given that The wind blows the kite horizontally to the left at a rate of 25 ft/min. i.e. [tex]\frac{dx}{dt}=25[/tex]
We are supposed to find At what rate is the length of the string changing when it is stretched out to 200 ft
z= 200
Using Pythagoras theorem :
[tex]x^2+y^2=z^2 ---1\\x^2+(150)^2=(200)^2\\x=\sqrt{(200)^2-(150)^2}\\x=132.28\\[/tex]
Now to find the rate at which the length of the string changing when it is stretched out to 200 ft
[tex]2x\frac{dx}{dt}+2y\frac{dy}{dt}=2z\frac{dz}{dt}\\2(132.28)(25)+2(150)(0)=2(200)\frac{dz}{dt}\\6614=2(200)\frac{dz}{dt}\\\frac{6614}{2(200)}=\frac{dz}{dt}\\16.535=\frac{dz}{dt}[/tex]
Hence The length of the string changing when it is stretched out to 200 ft at rate 16.535 ft/min