Question

A placekicker kicks a football at and angle of 40.0 degrees and the initial speed of the ball is 22 m/s. Ignoring air resistance, determine the maximum height that the ball attains.

Answer 1

Answer:

10.18m

Explanation:

in this problem, we are expected to solve for the maximum height of a projectile (the ball)

Firstly, the expression for maximum height is

h = u ^2 *sin ^2 θ /2 g

Given data

initial velocity u=22m/s

angle of projection, θ= 40degrees

substituting into the expression we have

h = 22^2 *sin (40)^2 /2 *9.81

h = 484*0.413 /19.62

h =199.892 /19.62

h=10.18m

The maximum height is 10.18m

Answer 2

The maximum height attains by ball is 48.64 meter.

The maximum height is given by using formula,

                  $h=\frac{u^{2}*sin2\theta }{g}$

Where u is initial velocity, and value of $g=9.8m/s^{2}$

Given that,   $u=22m/s,\theta=40,g=9.8m/s^{2}$

Substituting above values in formula.

             $h=\frac{(22)^{2}*sin80 }{9.8} =\frac{484*0.98}{9.8} =48.64m$

Hence, the maximum height attains by ball is 48.64 meter.

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