Given:
Parallel lines p and q are cut by transversal r.
m∠3=(3x + 4)° and m∠5=(2x + 11)°.
To find:
The relation between ∠3 and ∠5, then find the measure of angle 5.
Solution:
Parallel lines p and q are cut by transversal r as shown in the below figure.
From the figure it is clear that ∠3 and ∠5 are alternate interior angle. So, the values of these angles are equal.
[tex]m\angle 3=m\angle 5[/tex]
[tex](3x+4)^\circ=(2x+11)^\circ[/tex]
[tex]3x+4=2x+11[/tex]
Therefore, the required equation to solve for x is [tex]3x+4=2x+11[/tex].
Isolate variable terms.
[tex]3x-2x=11-4[/tex]
[tex]x=7[/tex]
The value of x is 7.
Now,
[tex]\angle 5=(2x+11)^\circ[/tex]
[tex]\angle 5=(2(7)+11)^\circ[/tex]
[tex]\angle 5=(14+11)^\circ[/tex]
[tex]\angle 5=25^\circ[/tex]
Therefore, the measure of angle 5 is 25°.