Respuesta :
Answer:
The height of the left bridge is 26.25 feet
Step-by-step explanation:
Let the left base of the bridge is at the origin and the x-axis represents the roadways as shown in the figure.
The given relationship between the variables x and y is
[tex]y = a(x - h)^2 + k[/tex]
where x is the horizontal distance from the left bridge support and y is the height of the cable above the roadway, (h,k) is the vertex of the parabola, and a is constant.
The vertex (h,k) of the parabola is the lowest point of the cable bridge.
As the lowest point of the cable is 6ft above the roadway and is a horizontal distance of 90 ft from the left bridge support, so, h=90 and k=6.
The given equation become,
[tex]y = a(x - 90)^2 + 6\cdots(i)[/tex]
At a horizontal distance of 30 ft, the cable is 15 ft above the roadway, so put x=30 and y=15 in the equation (i) to the value of constant a.
[tex]15 = a(30 - 90)^2 + 6[/tex]
[tex]\Rightarrow 15-6=3600a[/tex]
[tex]\Rightarrow a= 0.0025.[/tex]
Putting the value of constant [tex]a[/tex] in the equation (I) to get the required equation, we have
[tex]y = 0.0025(x - 90)^2 + 6[/tex]
As the left bridge is at the origin, so the the height of the left bridge is the value of y at origin.
Hence, put x=0 in the obtained equation to get the height of the bridge at the left side, we have
[tex]y= 0.0025(0 - 90)^2 + 6[/tex]
[tex]y=26.25[/tex]
Hence, the height of the left bridge is 26.25 feet.
Answer:
y=0.0025(x-90)^2+6
26.25ft
180ft
Step-by-step explanation
it is correct.