Which equation of the straight line is parallel to 4y=3x+5

Answer:
B
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
4y = 3x + 5 ( divide all terms by 4 )
y = [tex]\frac{3}{4}[/tex] x + [tex]\frac{5}{4}[/tex] ← in slope- intercept form
with slope m = [tex]\frac{3}{4}[/tex]
Parallel lines have equal slopes
Consider the given equations
A
y = 3x + 5 ⇒ m = 1 ← not parallel
B
4y = 3x - 1 ⇒ m = [tex]\frac{3}{4}[/tex] ← parallel
C
3y = 4x + 5 ⇒ m = [tex]\frac{4}{3}[/tex] ← not parallel
D
- 4y = 3x + 5 ⇒ m = - [tex]\frac{3}{4}[/tex] ← not parallel
E
4y = x + 5 ⇒ m = [tex]\frac{1}{4}[/tex] ← not parallel
The only line parallel to the given line is B
Line given in option B will be parallel to the line 4y = 3x + 5.
Equation of the line given in the question is,
Convert the equation into slope-intercept form,
[tex]y=\frac{3}{4}x+\frac{5}{4}[/tex]
Slope of the line = [tex]\frac{3}{4}[/tex]
y-intercept of the line = [tex]\frac{5}{4}[/tex]
Property of two parallel lines,
If two lines having slopes [tex]m_1[/tex] and [tex]m_2[/tex] are parallel,
Therefore, all the lines having slope [tex]\frac{3}{4}[/tex] will be parallel to the given line "4y = 3x + 5".
Option A
Equation of the line → y = 3x + 5
Slope of the line = 3
Option B
Equation of the line → 4y = 3x - 1
[tex]y=\frac{3}{4}x-\frac{1}{4}[/tex]
Slope of the line = [tex]\frac{3}{4}[/tex]
Option C
Equation of the line → 3y = 4x + 5
[tex]y=\frac{4}{3}x+\frac{5}{3}[/tex]
Slope of the line = [tex]\frac{4}{3}[/tex]
Option D
Equation of the line → -4y = 3x + 5
[tex]y=\frac{-3}{4}x-\frac{5}{4}[/tex]
Slope of the line = [tex]-\frac{3}{4}[/tex]
Option E
Equation of the line → 4y = x + 5
[tex]y=\frac{1}{4}x+\frac{5}{4}[/tex]
Slope of the line = [tex]\frac{1}{4}[/tex]
Therefore, line given in Option B will be parallel to the line having equation "4y = 3x + 5".
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