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Rock X is released from rest at the top of a cliff is on earth. A short time later, Rock y is released from rest from the same point as rock X. Both rocks fall for several seconds before landing on the ground directly below the cliff. Frictional forces are considered to be negligible. Which of the following graph correctly shows the vertical velocity of rock X as a function of time? Take the positive direction to the upward.​

Rock X is released from rest at the top of a cliff is on earth A short time later Rock y is released from rest from the same point as rock X Both rocks fall for class=

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Answer:

The graph that correctly shows the vertical velocity is B. since the velocity is negative and increases linearly over time

Explanation:

When an object is dropped from rest its movement is ruled only by the effect of gravity.

The acceleration of gravity [tex]g=9.8\ m/s^2[/tex] makes the object gain speed with a linear relation as shown:

vf = g.t

If we take the positive direction to be upward, then the speed will always be negative since the object will go against the positive direction.

Thus, the graph that correctly shows the vertical velocity is B. since the velocity is negative and increases linearly over time

From the given graphs, only the second graph (option B) started from rest (0) and later increased with time.

The given parameters;

  • Rock X
  • Rock y
  • initial velocity of Rock X = 0

The final vertical velocity of the rock X after a short time "t" is calculated as follows;

[tex]v_y_f = v_y_i + gt\\\\v_y_f = 0 + 9.8t[/tex]

The vertical velocity of the rock x will increase with time as it moves downwards.

Therefore, we can conclude that, from the given graphs, only the second graph (option B) started from rest (0) and later increased with time.

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