Question

297.85
Question 2
4 pts
If a sample of gas occupies 23.5 mL at 315 K and 14.8 atm of pressure, what volume will it occupy at 415 K and
12.3 atm?
Give your volume in ml, but do not include the units in the answer. Do not use scientific notation.
Question 3
4 pts

Answer 1

Answer:

37.25

Explanation:

$P_1$ = Initial pressure = $14.8\ \text{atm}$

$P_2$ = Final pressure = $12.3\ \text{atm}$

$V_1$ = Initial volume = $23.5\ \text{mL}$

$V_2$ = Final volume

$T_1$ = Initial temperature = $315\ \text{K}$

$T_2$ = Final temperature = $415\ \text{K}$

From ideal gas law we have

$PV=nRT$

$\Rightarrow PV\propto \dfrac{1}{T}$

So

$\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\Rightarrow V_2=\dfrac{P_1V_1T_2}{T_1P_2}\\\Rightarrow V_2=\dfrac{14.8\times 23.5\times 415}{315\times 12.3}\\\Rightarrow V_2=37.25\ \text{mL}$

The final volume is $37.25\ \text{mL}$