Answer:
The gas has a molar mass of around 87.4 g/mol
Explanation:
At STP, all gases are known to have the same molar volume of 22.4 L/mol. Since we know the volume (500. mL, or 0.500 L) and mass (1.95 g) of this particular gas, we can use stoichiometric conversion to find the molar mass.
[tex]\frac{0.500 L}{1} *\frac{1mol}{22.4L} =0.0223mol[/tex] We first convert the volume into moles.
[tex]\frac{1.95g}{0.0223mol} =87.4 g/mol[/tex] Then we find the ratio between the mass and moles to find molar mass.
