Answer:
Step - 2
Step-by-step explanation:
Given identity is,
[tex]\text{sin}(A-\frac{3\pi }{2})=\text{cosA}[/tex]
We will take the left hand side of the equation and prove it equal to the right hand side of the equation.
[tex]\text{sin}(A-\frac{3\pi }{2})=\text{sinA}\text{cos}(\frac{3\pi }{2})}-\text{sin}(\frac{3\pi}{2})\text{cosA}[/tex] [Step - 1]
= sinA(0) - cosA(-1) [Step - 2]
= sinA(0) + (1)cosA [Step - 3]
= 0 + cos A [Step - 4]
= cosA [Step - 5]
There is an error in Step - 2 .
It should be sinA(0) - cosA(-1) in place of sinA(0) + cosA(-1).