Respuesta :

caylus
Hello,

[tex]y= \sqrt{ x*sin(x) } \\ y'= \dfrac{sin(x)+x*cos(x)}{2 \sqrt{x*sin(x)} } [/tex]
Here is the answer of the given mathematical problem above:
In order to differentiate f(x)= square root of x times sin x, you do this.
Use the product rule so that f′(x)=f(x)g′(x)+f′(x)g(x) when f(x)=x√ andg(x)=sin(x)
Next, solve for the derivative of sqrt(x) and sinx first and then plug into the equation for the product rule.
The result would be the derivative of sqrt(x) is 1/2x^-1/2 and derivative of sinx is cosx.
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