Answer:
Yes
Explanation:
The given parameters are;
The speed with which the fastball is hit, u = 49.1 m/s (109.9 mph)
The angle in which the fastball is hit, θ = 22°
The distance of the field = 96 m (315 ft)
The range of the projectile motion of the fastball is given by the following formula
[tex]Range = \dfrac{u^2 \times sin(2\cdot \theta)}{g}[/tex]
Where;
g = The acceleration due to gravity = 9.81 m/s², we have;
[tex]Range = \dfrac{49.1^2 \times sin(2\times22^{\circ})}{9.81} \approx 170.71 \ m[/tex]
Yes, given that the ball's range is larger than the extent of the field, the batter is able to safely reach home.
