Question

How many moles of NH3 can be produced from 3.76 moles of nitrogen
in the following reaction:
N2 (g) + 3 H2 (g) → 2 NH; (g)

Answer 1

3.76 mole N x 2 mole NH3 / 1 mole of N2
= 7.25 mole NH3

Answer 2

The number of moles of NH₃ obtained from the reaction is 7.52 moles

The balanced equation is given below:

N₂ + 3H₂ —> 2NH₃

From the balanced equation above,

1 mole of N₂ reacted to produce 2 moles of NH₃.

Finally, we shall the number of mole of NH₃ produced by the reaction of 3.76 moles of N₂. This can be obtained as follow:

From the balanced equation above,

1 mole of N₂ reacted to produce 2 moles of NH₃.

Therefore,

3.76 moles of N₂ will react to produce = 3.76 × 2 = 7.52 moles of NH₃.

Thus, 7.52 moles of NH₃ were obtained from the reaction.

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