Respuesta :
Answer:
I will assume that you mean
STP (Standard Temperature and Pressure)
21
3
≈
7 L
Explanation:
Since we know that
1 mole
of an ideal gas occupies
22.4 L
at
STP
then can establish the following relationships:
22.4 L
1 mole
or
1 mole
22.4 L
Knowing that, we can solve for the volume occupied by the helium gas,
0.35
mole
1
⋅
22.4 L
1
mole
=
7.84 L
as
7.84 L
−
−
−
−
−
The answer makes sense because if
1 mole
occupies
22.4 L
, then
0.35 moles
(roughly a third of the moles) will occupy a third of
22.4 L
(
if we round down 22.4 L to 21 L
)
−
−
−
21
3
≈
7 L
The volume occupied by 0.34 moles of Helium Gas is 7.62 L.
What is a noble gas ?
Any gas from the group of rare gases that include helium, neon, argon, krypton, xenon, and usually radon and that exhibit great stability and extremely low reaction rates. — called also inert gas.
They have properties tending to an ideal gas.
It is asked that what volume will be occupied by 0.34 moles Helium Gas
The ideal gas equation is written as
PV = nRT
At STP , T = 273 K
P= 1atm
R = 0.0821 L(atm) mol⁻¹K⁻¹
Substituting the values
1 * V = 0.34 * 0.0821 * 273
V = 7.62 L
Therefore the volume occupied by 0.34 moles of Helium Gas is 7.62 L.
To know more about Noble Gas
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