Question

What is the equation of a line passing through the point (4,-1) and parallel to the line whose equation is 2y-x=8

Answer 1

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Answer:

  2y -x = -6

Step-by-step explanation:

You can use the same x- and y-coefficients. You just have to change the constant on the right. Put the point values into the left expression to see the new constant.

  2y -x = 2(-1)-(4) = -6

The parallel line is ...

  2y -x = -6