Question

Find the 58th term of the arithmetic sequence -28, -13, 2, ...

Answer 1

Answer:

             a₅₈ = 377

Step-by-step explanation:

$a_1=-28\\a_2=-13\\\\d=a_2-a_1=-13-(-28)=-13+28=15\\\\a_n=a_1+d(n-1)\\\\a_{58}=-28+15(58-1)=-28+15\cdot27=-28+405=377$