A container of gas has a volume of 280 mL at a temperature of 22 Celsius if the pressure remains constant what is the volume 44 Celsius?

Respuesta :

Answer:

300.9mL

Explanation:

Given parameters:

V₁  = 280mL

T₁ = 22°C

T₂  = 44°C

Unknown:

V₂ = ?

Solution:

To solve this problem, we apply Charles's law;

  it is mathematically expressed as;

            [tex]\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }[/tex]

We need to convert the temperature to kelvin;

       T₁ = 22°C = 22 + 273 = 295K

       T₂  = 44°C = 44 + 273  = 317K

Input the parameters and solve;

        [tex]\frac{280}{295}[/tex]   = [tex]\frac{V_{2} }{317}[/tex]

  V₂ x 295 = 280 x 317

  V₂ = 300.9mL

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