Answer: 0.884736
Step-by-step explanation:
Given: The proportion of all air travel departs on time: p= 0.96
Total flights : n= 3
Let x be the number of flights on time.
As there are two cases either flight on time or not, so it is a binomial case.
Binomial distribution formula: [tex]P(X=x)=\ ^nC_xp^x(1-p)^{n-x}[/tex]
The probability that all of them depart on time = [tex]P(X=3)=\ ^3C_3(0.96)^3(1-0.96)^0=(1)(0.96)^3=0.884736[/tex]
The probability that all of them depart on time = 0.884736
