Question

When copper is bombarded with high-energy electrons, X rays are emitted. Calculate the energy (in joules) associated with the photons if the wavelength of the X rays is 0.154 nm.

Answer 1

Answer:

E = 12.92 × 10^(-16) J

Explanation:

Formula for energy is;

E = hc/λ

Where;

h is Planck's constant = 6.63 x 10^(-34) J.s

c is speed of light = 3 × 10^(8) m/s

λ is wavelength = 0.154 nm = 0.154 × 10^(-9) m

E = (6.63 x 10^(-34) × 3 × 10^(8))/(0.154 × 10^(-9))

E = 12.92 × 10^(-16) J

Answer 2

The energy associated with the photons of X rays with a wavelength of 0.154 nm is 1.29 × 10⁻¹⁵ J.

When copper is bombarded with high-energy electrons, X rays, with a wavelength of 0.154 nm (λ) are emitted.

We can calculate the energy (E) associated with the photons of these X rays using the Planck-Einstein relation.

$E = \frac{h \times c }{\lambda } = \frac{(6.63 \times 10^{-34}J.s ) \times (3.00 \times 10^{8}m/s ) }{0.154 \times 10^{-9} m } ]= 1.29 \times 10^{-15} J$

where,

• h: Planck's constant

• c: speed of light

The energy associated with the photons of X rays with a wavelength of 0.154 nm is 1.29 × 10⁻¹⁵ J.

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