Answer:
probability = 0.5294
1) what i know is that there are two machines
2) the probability of choosing a machine that pays 20% of the time
3) expected answer = 0.5294 = 52.94%
4) buy making some assumptions while making the calculations
5) yes
Step-by-step explanation:
Given data:
Number of machines = 2
Assuming probability of machine 2 = 20% = 0.20
Assuming probability of machine 1 = 10% = 0.10
since both machines have the ability to be generous i.e. pay 20% all the time
P( machine 1 is generous ) = P( machine 2 is generous ) = 0.5
this is since there are only two machines
hence find the probability that the chosen machine ( machine 1 ) is the generous machine after the player losses its first bet
P ( Machine 1 is generous | first bet lost )
= [tex]\frac{P( machine 1 is generous n lost) }{p(lost)}[/tex] = [tex]\frac{(1-p(pays|machine 1 is generous))*p(machine 1 is generous)}{[((1-0.10)*0.5)+ ((1-0.20)*0.5)]}[/tex]
= [tex]\frac{(1-0.10)*0.5}{0.85}[/tex] = 0.5294
This the probability that Machine 1 is generous after the player losses the first bet
1) what i know is that there are two machines
2) the probability of choosing a machine that pays 20% of the time
3) expected answer = 0.5294 = 52.94%
4) buy making some assumptions while making the calculations
5) yes