Answer:
61.75 °C
Explanation:
According to the law of conservation of energy,
Qtin = - (Qliquid)
(m×c×∆T)tin = -(m×c×∆T) ethylene glycol
Where; m = mass
c = specific heat capacity
∆T = change in temperature
According to the information given in this question;
For tin: m= 10.04g, c= 0.213 J/g °C, initial temperature= 14.77 °C, final temperature=?
For ethylene glycol: m= 24.11g, c= 2.36 J/g °C, initial temperature= 63.52 °C, final temperature=?
Hence; (m×c×∆T)tin = -(m×c×∆T) ethylene glycol
10.04 × 0.213 × (T - 14.77) = - {24.11 × 2.36 × (T - 63.52)}
2.139 (T - 14.77) = - {56.899 (T - 63.52)}
2.139T - 31.59 = -56.899T + 3614.225
2.139T + 56.899T = 31.59 + 3614.225
59.038T = 3645.815
T = 3645.815/59.038
T = 61.75 °C
The final temperature of tin and ethylene glycol is 61.75 °C
