Question

In her last two years in college, Marlene received $42,000 in loans. The first year, she received a loan that was $6,000 less than three times the amount of the second year's loan. Call the amount that Marlene received her first year f and the amount she received in her second year s.

Answer 1

Answer:

First year = 30000

Second year = 12000

Step-by-step explanation:

Given

$Loan = \ 42000$

Represent first year with f and second year with s.

So, we have:

$s + f = 42000$

and

$f = 3s - 6000$

Required

Solve for f and S

Substitute 3s - 6000 for f in the first equation.

$s + f = 42000$

$s + 3s - 6000 = 42000$

$4s - 6000 = 42000$

Collect Like Terms

$4s = 42000 + 6000$

$4s = 48000$

Solve for s

$s = 48000/4$

$s = 12000$

Substitute 12000 for s in $f = 3s - 6000$

$f = 3 * 12000 - 6000$

$f = 36000 - 6000$

$f = 30000$