An iscosceles right angled triangle is shown

Answer : x = 4
Step-by-step explanation:
Area = 1/2 × base × height
Area= 200cm²
base = 5x
height = 5x
200cm² = 1/2 × base × height
200 = 1/2 × 5x × 5x
200 = 1/2 × 25x²
2( 200) = 25x²
400 = 25x²
16 = x²
4 = x
Answer: " x = 4 " .
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Step-by-step explanation:
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The formula for the area of a triangle:
Area, "A" = (1/2) * base * height;
that is: A = (1/2) * b * h ;
From our given problem and image/diagram:
A = 200 cm² ;
b = 5x ;
h = 5x ;
We are asked to find the value for "x" ;
A = (1/2) * b * h ;
Plug in our known values:
200 cm² = (1/2) * 5x * 5x ;
Simplify:
200 cm² = (1/2)*(25x²) ;
200 cm² = (12.5)x² ;
⇔ (12.5)x² = 200 cm² ;
Divide each side by: " (12.5)" ;
(12.5)x² / (12.5) = (200 cm²)/(12.5) ;
to get: x² = 16 ;
Take the positive square root of each side of the equation; to get the value for "x" ;
⁺ [tex]\sqrt{x^{2} } =[/tex] ⁺ [tex]\sqrt{16}[/tex] ;
to get:
x = 4 .
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Good luck to you in your academic endeavors!
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