Question

A jet airliner moving initially at 538 mph (with respect to the ground) to the east moves into a region where the wind is blowing at 937 mph in a direction 23 degrees north of east. What is the new speed of the aircraft with respect to the ground. Answer in units of mph

Answer 1

Answer:

The speed is "1447.576 mph".

Explanation:

The given values are:

Direction (north to east)

= 23°

Wind's speed

= 937 mph

Jet moving at a speed

= 538 mph

Now,

The velocity of jet airliner with respect to the ground will be:

⇒ $v=v_{1}+v_{2}$

⇒ $v=\sqrt{(538)^2+(987)^2+2(538)(937)\times Cos23^{\circ}}$

⇒    $=1447.576 \ mph$