Question

the kind of bond present in CUSO4.5H20​

Answer 1

Answer:

Both ionic bonds and covalent bonds (coordinate and non-coordinate) are present in crystalline $\rm CuSO_4\cdot 5\, H_2O$.

Explanation:

$\rm CuSO_4\cdot 5\, H_2O$ can be formed by adding water to the anhydrous salt $\rm CuSO_4$.

$\rm CuSO_4$ itself is an ionic compound consisting of $\rm Cu^{2+}$ ions and $\rm {SO_4}^{2-}$ ions. Ionic bonds are present between these ions. However, within each sulfate $\rm {SO_4}^{2-}$ ion, covalent bonds connect the central sulfur atom to each of the oxygen atoms.

Water molecules $\rm H_2O$ are highly polar. Partial negative charges surround the oxygen atom in each water molecule.

When water is added to anhydrous $\rm CuSO_4$, the negatively-charged portion of these $\rm H_2O\!$ molecules would be attracted to the positively-charged $\rm Cu^{2+}$ ions in $\rm CuSO_4\!$.

Lone pairs on oxygen atoms in $\rm H_2O\!\!$ would form coordinate covalent bonds with $\rm Cu^{2+}\!$ ions. (These bonds are considered "coordinate" because both electrons in each of these bonds come from the oxygen atom, not the $\rm Cu^{2+}$ ion.) That would produce coordination complexes with one $\rm Cu^{2+}\!\!$ ion and five $\rm H_2O\!\!\!$ "ligands" each.

Because the $\rm H_2O$ ligands carry no electric charge, each of these complexes would also carry a charge of $(+2)$ (same as the charge on one $\rm Cu^{2+}\!\!$ ion.) Ionic bonds would be present between the positively-charged coordination complexes and the negatively-charged $\rm {SO_4}^{2-}$ ions.

Summary:

• Covalent bonds are present within $\rm {SO_4}^{2-}$ ions and $\rm H_2O$ ligands.
• Coordinate covalent bonds are present between $\rm H_2O$ ligands and $\rm Cu^{2+}$ ions.
• Ionic bonds are present between $\rm {[Cu\, (H_2O)_5]}^{2+}$ coordination complexes and sulfate ions $\rm {SO_4}^{2-}$.