Question

John has 1 1/4 acres of land. it takes 80 1/2 pounds of fertilizer to cover one acre. How much fertilizer does John need to cover his land.

Answer 1

$area \: of \: land \: with \: john \: = 1 \frac{1}{4} \: acres \ \\ \\ = \frac{(4 \times 1) + 5}{4} \\ \\ \\= \frac{9}{4} \: acres$

Quantity of fertilizer needed to cover 1 acre of land :-

$\: \ \\ = 80 \frac{1}{2} \: pounds \\ \\ = \frac{(2 \times 80) + 1}{2} \\ \\ = \frac{81}{2} \: pounds$

Quantity of fertilizer needed by John to cover his land :-

$\frac{9}{4} \times \frac{81}{2}$

$\frac{(9 \times 2 ) \times (81 \times 4)}{8}$

$\frac{(18 \times 324)}{8}$

$= \frac{5832}{8}$

$= 729 \: pounds$

∴ John needs 729 pounds of fertilizer to cover his land .