Question

PLEASE HELP!! Salmon often jump waterfalls to reach their
breeding grounds.
Starting downstream, 3.41 m away from a
waterfall 0.397 m in height, at what minimum
speed must a salmon jumping at an angle of
28.4° leave the water to continue upstream?
The acceleration due to gravity is 9.81 m/s2
Answer in units of m/s.

Answer 1

Answer:

7.13781 m/s

Explanation:

X-direction             | Y-direction

$x=v_{xo}t+\frac{1}{2}a_{x}t^2$      | $y=v_{yo}t+\frac{1}{2}a_{y}t^2$

$3.41=v_{o}cos(28.4)t$  | $0.397=v_{yo}sin(28.4)t+\frac{1}{2} (-9.81)t^2$

$3.41=v_{o}(0.87964)t$  | $0.397=v_{yo}sin(28.4)(\frac{3.87658}{v_{o} })+\frac{1}{2} (-9.81)(\frac{3.87658}{v_{o} })^2$

$\frac{3.41}{0.87964}=v_{o}t$             | $0.397=1.84379-\frac{73.71171}{v^2}$

$\frac{3.87658}{v_{o} } =t$                | $7.13781=v$