Question

The first side of a triangle is 2 inches shorter than three times the second side. The third side is 1 inch longer than twice the second side. If the perimeter of the triangle is 101 inches, how long is each side?

(Answer to get brainliest)

Answer 1

Answer:

17in, 49in, 35in

Step-by-step explanation:

I did this in my RSM homwork and it is correct.

First, I added the two inches shorter to the 101, then subtracted 1 longer and got 102.

then divide 102 by how many second lengths, 6. so 102 ÷ 6 = 17

17 is the second length.

3x17-2=49 (another length)

2x17+1=35 (last length)

and there is your answer!

Answer 2

First side : 49

Second side : 17

Third side : 35

What is the perimeter of a triangle?

If triangle has sides a, b, c , then the perimeter of that triangle will be P= a +b +c.

Now, according to the question

Let  second side be (b) = x unit

then, First side will be  (a)= 3x-2 unit

and Third side will be  (c)= 2x + 1 unit

since , perimeter is 101

P = a + b + c

x + 3x -2 + 2x + 1 = 101

6x - 1 = 101

x= 17

hence , b = 17 unit

a= 3*17 - 2 =49 unit

c = 2*17 +1 = 35 unit

Lets learn more about perimeter of a triangle

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