Question

4. Calculate the energy (E) and wavelength (1) of a photon of light with a frequency of
6.165 x 1014 Hz.
PLEASE HELP!!

Answer 1

Answer: E= 4.085 x 10^-19 J ; Wavelength= 4.862 x 10^-7 m

Explanation:

Sorry for the messy work, but I hope this helps.

Remember:

Plancks constant (h)=  6.626x10^-34 Js

Speed of light (c) = 2.998 x 10^8 ms^-1

What I did:

I found the energy first with the given frequency. Don't forget to convert your units to s^-1! They are actually the same, you dont need to do math for that conversion, just a simple Hz to s^-1.

For the wavelength, I multiplied plancks constant (h) and speed of light (c) together. With that number I divided by the energy found which 4.085 x 10^-19J. Also, be sure to cross off the units because it can get very confusing.  

Answer 2

The energy of the photon is 4.08 x 10⁻¹⁹ J

The wavelength of the photon is 2.58 x 10⁻⁶ m

The given parameters;

frequency of the photon, f = 6.165 x 10¹⁴ Hz

The energy of the photon is calculated as;

E = hf

where;

h is Planck's constant = 6.626 x 10⁻³⁴ Js

E = (6.626 x 10⁻³⁴)( 6.165 x 10¹⁴)

E = 4.08 x 10⁻¹⁹ J

The wavelength of the photon is calculated as;

v = fλ

where;

v is the speed of light = 3 x 10⁸ m/s

$\lambda = \frac{v}{f} \\\\\lambda = \frac{3\times 10^8}{1.165\times 10^{14}} \\\\\lambda = 2.58 \times 10^{-6} \ m$

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