Answer:
since [tex]17+24=41[/tex]
a) [tex]\frac{\binom{17}{12}}{\binom{42}{12}}[/tex]
b) [tex]\frac{\binom{24}{12}}{\binom{42}{12}}[/tex]
c) [tex]\frac{\binom{17}{8} \cdot \binom{24}{4}}{\binom{42}{8}\cdot\binom{36}{4}}[/tex]
d) [tex]\frac{\binom{17}{6}\cdot\binom{24}{6}}{\binom{17}{6}\cdot\binom{36}{6}}[/tex]
Just calculate these. If there is anything wrong just let me know.