Which equation represents a line which is perpendicular to the line
6x + 7y = -42?
Somebody please help?
![Which equation represents a line which is perpendicular to the line 6x 7y 42 Somebody please help class=](https://us-static.z-dn.net/files/d51/3d35a137f355114a97e80263ec67a93f.png)
Answer:
y = [tex]\frac{7}{6} x - 5[/tex]
Step-by-step explanation:
Given expression:
6x + 7y = -42
To find an equation perpendicular to this, it implies the slope must be a negative inverse of the given one.
Solution:
Equation of any straight line is given as;
y = mx + c
where x and y are the coordinates
m is the slope
c is the intercept
Let us now find the slope of the line;
6x + 7y = -42
7y = -6x - 42
divide through by 7 to give;
y = [tex]-\frac{6}{7} x[/tex] - 6
The slope is [tex]-\frac{6}{7}[/tex]
A line perpendicular will have a slope of a negative inverse;
- ( [tex]-\frac{7}{6}[/tex] ) = [tex]\frac{7}{6}[/tex]
The answer is A.