Answer:
Step-by-step explanation:
Ist method - Area of the triangle + Area of the trapezium
Area of triangle = 1/2 × b × h
here, b = 8 cm but h is not given
so we will find h by pythagoras theorem
AC^2 = AB^2 + BC^2
10^2 = 8^2 + BC^2
100 = 64 + BC^2
BC^2 = 36
BC = √36
BC = 6
∴ h = 6cm
area of triangle = 1/2 × b × h
= 1/2 × 8 × 6
= 24 cm^2
Area of trapezium = 1/2 ( a + b ) h
Here a = 13cm
b = 25 - 8 = 17 cm
h = 6 cm
So area = 1/2 ( a + b ) h
= 1/2 ( 13 + 17 ) 6
= 90 cm^2
So total area = Area of the triangle + Area of the trapezium
= 24 cm^2 + 90 cm^2 = 114 cm^2
2nd method - Area of the entire figure
Since the figure is a trapezium,
Area of trapezium = 1/2 ( a + b ) h
here, a = 13cm
b = 25 cm
h = 6 cm
Area of trapezium = 1/2 ( a + b ) h
= 1/2 ( 13 + 25 ) 6
= 114 cm^2
Hope this helps
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