Answer:
[tex]V_2=35.68\ L[/tex]
Explanation:
Initial volume, V₁ = 300 L
Temperature, T₁ = 227°C
New temperature, T₂ = 27°C
We need to find the volume of gas occupied when the temperature is 27°C.
It is based on Charle's law. A/c to Charle's law,
[tex]V\propto T[/tex] (at constant pressure)
[tex]\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{300\times 27}{227}\\\\V_2=35.68\ L[/tex]
Hence, the new volume is 35.68 L.