Question

Determine the amount of energy (heat) in Joules and Kcal required to raise the temperature 0f 98.5 grams water from 37.0 0C to 75.0 0C.

Answer 1

Answer:

15660.712J

Explanation:

Q = m × c × del T

Q(energy) = ?

m (mass) = 98.5g

c = 4.184J

del T = 75-37 = 38 °C

Q = 98.5 × 4.184 × 38

Q = 15660.712 J